Suppose you have two small pith balls that are 5.5 cm apart
Answer:- The question is missing, though, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is: F = keq1q2/r2
Where ke = 8.99 109 Nm2C-2 is the Coulomb’s constant, q1 = q2 = 29 nC = 29 10-9 C is the intensity of the two charges, and r = 5.5 cm = 0.055mis the distance between them.
Substituting these numbers into the equation, we get
F = 2.5 10-3 N
The force is repulsive, since the charges have similar sign and so they repel each other.
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